P b 0.5 p a ∩ b 0.4. find p a b
Splet05. mar. 2016 · Being $A$ and $B$ two events. Suppose that $P(A) = 0.4$ while $P(A \cup B) = 0.7$ and $P(B) = p$. The question is: For which value of $p, A$ and $B$ will be …
P b 0.5 p a ∩ b 0.4. find p a b
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Splet30. mar. 2024 · Ex 16.3, 12Check whether the following probabilities P(A) and P(B) are consistently definedP(A) = 0.5, P(B) = 0.7, P(A ∩ B) = 0.6P(A) & P(B) are consistently defined ifP(A ∩ B) < P(A) & P(A ∩ B) < P(B) P(A ∪ B) > P(A) & P(A ∪ B) > P(B) Given P(A) = 0.5, P(B) = 0.7, P(A ∩ B) = 0. Splet28. sep. 2024 · I know P ( A ∩ B) = 0.4 So I thought the answer is 1 because P ( A B) = P ( A ∩ B) P ( B) = 1 But the final answer is D: 2 3 The reasoning behind the answer is as follows P ( A ∩ B) = P ( B) ⋅ P ( A B) = P ( A ∩ B) P ( A) = 2 3. But I don't understand why you divide by P ( A) in the above.
SpletTo find: The probability of getting a 2 or 3 when a die is rolled. Let A and B be the events of getting a 2 and getting a 3 when a die is rolled. Then, P (A) = 1 / 6 and P (B) = 1 / 6. In this case, A and B are mutually exclusive as we cannot get 2 and 3 in the same roll of a die. Hence, P (A∩B) = 0. Using the P (A∪B) formula, SpletLet us consider the venn diagram of A and B to find P (A ∩ ¯ ¯¯ ¯ B) The shaded region is P(A). It can also be obtained by removing A intersection B from A ⇒ P (A ∩ ¯ ¯¯ ¯ B) = P (A) − P (A ∩ B) We are given P (A B) = 0.2 If we know P (A ∩ B), then we can find the value of P (A ∩ ¯ ¯¯ ¯ B) For that we can use the ...
Splet08. okt. 2024 · Best answer. P (B/A) = 0.5. ⇒ P (B ∩ A)/P (A) = 0.5. (i.e.,) P (B ∩ A)/0.4 = 0.5. ∴ P (B ∩ A) = 0.4 × 0.5 = 0.2. (i.e.,) P (A ∩ B) = 0.2. P (A ∪ B)= P (A) + P (B) – P (A ∩ B) P … SpletTour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site
SpletIf P (A) = 0.4, P (B) = 0.3 and P (B/A) = 0.5, Find P (A ∩ B) and P (A/B). - Mathematics Shaalaa.com. CBSE. Question Papers. Textbook Solutions. MCQ Online Mock Tests. If P …
SpletPROBABILITY THEORY 1. Prove that, if A and B are two events, then the probability that at least one of them will occur is given by P(A∪B)=P(A)+P(B)−P(A∩B). China plates that have been fired in a kiln have a probability P(C)= 1/10 of being cracked, a probability P(G)=1/10 of being imperfectly glazed and a probability P(C∩G)=1/50 or being both both cracked and function of rheostatSpletTour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site girl injected with hivSpletP (A ∩ B) = P (A) × P (B A) = (3/10) × (7/9) = 0.2333 Union of A and B In probability, the union of events, P (A U B), essentially involves the condition where any or all of the events being considered occur, shown in the Venn … function of rheostat class 10SpletIf A and B are events such that P (A B) = P(B A), then (A) A ⊂ B but A ≠ B (B) A = B (C) A ∩ B = Φ (D) P(A) = P(B) Q. A and B are two events such that P(A) = 0.54, P(B) = 0.69 and P(A … function of rhetorical questionSpletCorrect option is A) P( AB)= P(A)P(B∩A) 0.4= 0.8P(B∩A) ∴P(B∩A)=0.32, P(A∩B)=0.32 thenP( BA)= P(B)P(A∩B)=( 0.50.32)=0.64 andP(A∪B)=P(A)+P(B)−P(A∩B) =0.8+0.5−0.32 =0.98 Was this answer helpful? 0 0 Similar questions If A=4,6,7,8,9,B=2,4,6 and C=1,2,3,4,5,6, then find (i) A∪(B∩C) (ii) A∩(B∪C) (iii) A∖(C∖B) Medium View solution > girl in jack reacherSpletIf P (A) = 0.4, P (B) = 0.3 and P (B/A) = 0.5 , find P (A∩ B) and P (A/B) . Question If P(A)=0.4,P(B)=0.3 and P(B/A)=0.5, find P(A∩B) and P(A/B) . Medium Solution Verified by Toppr P(A)=0.4,P(B)=0.3 P(B/A)=0.5 P(B/A)= P(A)P(A∩B)=0.5 P(A∩B)=0.5×0.4=0.2 P(A/B)= P(B)P(A∩B)= 0.30.2=32. Was this answer helpful? 0 0 Similar questions girl in italy that killed her husbandSpletP (A ∩ B) = P (B ∩ A) = P (A). P (B) This rule is called as multiplication rule for independent events. Step 2: Click the blue arrow to submit. Choose "Find P(A∩B) for Independent … girl in it lyrics